-15x^2+49x+22=0

Solution for -15x^2+49x+22=0 equation:

-15x^2+49x+22=0

a = -15; b = 49; c = +22;
Δ = b2-4ac
Δ = 492-4·(-15)·22
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-61}{2*-15}=\frac{-110}{-30}
=3+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+61}{2*-15}=\frac{12}{-30}
=-2/5
$